X+y=5;x-y=3 solve.

1.	X+y=5;x-y=3 solve.
Answer» $\large{\underline{\underline{\mathfrak{\green{\sf{QUESTION:-}}}}}}$ . $\:(<klux>X</klux>+y)\:=\:5$ And, $\:(x-y)\:=\:3$ Solve this $\large{\underline{\underline{\mathfrak{\sf{SOLUTION:-}}}}}$ . $\large{\underline{\mathfrak{\sf{Given\:Equation:-}}}}$ . $\:(x+y)\:=\:5$ ...(1) $\:(x-y)\:=\:3$ .....(2) $\large{\underline{\underline{\mathfrak{\sf{Find\:Here:-}}}}}$ . VALUE of x and y $\large{\underline{\underline{\mathfrak{\sf{Explanation:-}}}}}$ . [ SUM of these equation ] $\implies\:(2y)\:=\:8$ $\implies\:y\:=\frac{8}{2}$ $\implies\boxed{\boxed{\:y\:=\:4}}$ Now, keep value of y in (1) $\implies\:(x+4)\:=\:5$ $\implies\:x\:=\:5-4$ $\implies\boxed{\boxed{\:x\:=\:1}}$ $\large{\underline{\underline{\mathfrak{\green{\sf{Answer:-}}}}}}$ . $\:Value\:of\:x\:=\:1$ $\:Value\:of\:y\:=\:4$ $\large{\underline{\underline{\mathfrak{\green{\sf{Answers:Verification:-}}}}}}$ . Keep value of x and y in equation (1) $\implies\:(1+4)\:=\:5$ $\implies\:5\:=\:5$ L.H.S.= R.H.S. So, we can say that value of x and y are exits this equation .

Answer»

$\large{\underline{\underline{\mathfrak{\green{\sf{QUESTION:-}}}}}}$ .