( x + y ) ^ { - 1 } \cdot ( x ^ { - 1 } + y ^ { - 1 } ) = x ^ { p } y – InterviewSolution

1.	( x + y ) ^ { - 1 } \cdot ( x ^ { - 1 } + y ^ { - 1 } ) = x ^ { p } y ^ { q } , \text { prove that } p + q + 2 = 0
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