1.

X square +4 root 3 x +12 =0 find roots

Answer»

Answer:

GIVEN the equation is x^2+4√3x+12=0

comparing with the equation ax^2+bx+c=0

a=1,b=4√3,c=12

either x=-4√3+√48-48/2=-4√3/2 or, x=-4√3-√0/2

=-4√3/2

Step-by-step EXPLANATION:

here, (D) = b^2 - 4ac=0

so, the equation have two real and equal roots..

Hope it HELPS you dude..


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