X is an ionic compound containing only magnesium, aluminium andoxyge

1.	X is an ionic compound containing only magnesium, aluminium andoxygen. Which of the following can bethe formula of X?a. Mg2Alo4b. MgAl204C. MgAlO4d. Mg4Alo2
Answer» er:- The FORMULA of 'X' is MgAl₂O₄ [Option.b] Explanation:- → Charge of Magnesium ion = +2 → Charge of ALUMINIUM ion = +3 → Charge of Oxide ion = -2 Now, we KNOW that net charge of an ionic compound is always zero. So among the given options, the compound having net charge zero will be the ANSWER. For Option (a):- Net charge :- = 2(+2) + 1(+3) + 4(-2) = 4 + 3 - 8 = -1 For option (b):- Net charge :- = 1(+2) + 2(+3) + 4(-2) = 2 + 6 - 8 = 0 For option (c):- Net charge :- = 1(+2) + 1(+3) + 4(-2) = 2 + 3 - 8 = -3 For option (d):- Net charge :- = 4(+2) + 1(+3) + 4(-2) = 8 + 3 - 8 = +3 ________________________________ The net charge in MgAl₂O₄ is zero, so it is the required answer!

X is an ionic compound containing only magnesium, aluminium andoxygen. Which of the following can bethe formula of X?a. Mg2Alo4b. MgAl204C. MgAlO4d. Mg4Alo2

Answer»

er:-

The FORMULA of 'X' is MgAl₂O₄ [Option.b]

Explanation:-

→ Charge of Magnesium ion = +2

→ Charge of ALUMINIUM ion = +3

→ Charge of Oxide ion = -2

Now, we KNOW that net charge of an ionic compound is always zero. So among the given options, the compound having net charge zero will be the ANSWER.

For Option (a):-

Net charge :-

= 2(+2) + 1(+3) + 4(-2)

= 4 + 3 - 8

= -1

For option (b):-

Net charge :-

= 1(+2) + 2(+3) + 4(-2)

= 2 + 6 - 8

= 0

For option (c):-

Net charge :-

= 1(+2) + 1(+3) + 4(-2)

= 2 + 3 - 8

= -3

For option (d):-

Net charge :-

= 4(+2) + 1(+3) + 4(-2)

= 8 + 3 - 8

= +3

________________________________

The net charge in MgAl₂O₄ is zero, so it is the required answer!