x is a point on the sideBC of Δrespectively meetiProve that TX TB x T

1.	x is a point on the sideBC of Δrespectively meetiProve that TX TB x TCpoint on the side BC of AABC. XM and XN are drawn parailel to AB and ACparallel to AB and AÇAC in M. MN produccd meets CB produced at 1Tng AB in N and
Answer» XM \|\| AB, XN \|\| AC TX² = TB x TC BN \|\| XM For ΔTXM we have BN \|\| XM Now we will use BASIC PROPORTIONALITY THEOREM TB/TX = TN/TM --- (this is equation 1) XN \|\| AC XN \|\| CM In ΔTMC we have XN \|\| CM Again we will use BASIC PROPORTIONALITY THEOREM TX/TC = TN/TM --- (this is equation 2) Now we will compare equation 1 and equation 2 TB/TX = TX/TC TX² = TB x TC (proved)

x is a point on the sideBC of Δrespectively meetiProve that TX TB x TCpoint on the side BC of AABC. XM and XN are drawn parailel to AB and ACparallel to AB and AÇAC in M. MN produccd meets CB produced at 1Tng AB in N and

Answer»

XM || AB, XN || AC

TX² = TB x TC

BN || XM

For ΔTXM we have

BN || XM

Now we will use BASIC PROPORTIONALITY THEOREM

TB/TX = TN/TM --- (this is equation 1)

XN || AC

XN || CM

In ΔTMC we have

XN || CM

Again we will use BASIC PROPORTIONALITY THEOREM

TX/TC = TN/TM --- (this is equation 2)

Now we will compare equation 1 and equation 2

TB/TX = TX/TC

TX² = TB x TC (proved)