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X is a point on the side BC of AABC XM and XN are drawn parald ACd atto AB anrespectively meeting AB in N and AC in M MIN produced meets CB produceProve that TX2 = TB × TC과떼 |
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Answer» XM || AB, XN || AC TX² = TB x TC BN || XM For ΔTXM we have BN || XM Now we will use BASIC PROPORTIONALITY THEOREM TB/TX = TN/TM --- (this is equation 1) XN || AC XN || CM In ΔTMC we have XN || CM Again we will use BASIC PROPORTIONALITY THEOREM TX/TC = TN/TM --- (this is equation 2) Now we will compare equation 1 and equation 2 TB/TX = TX/TC TX² = TB x TC (proved) |
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