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`x(dy)/(dx)=y(logy-logx+1)`A. `logx/y=cy`B. `logy/x=cy`C. `logy/x=cx`D. None of these |
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Answer» Correct Answer - C `(dy)/(dx)= y/x[logy/x+1]` Put `y=vx` `v+x(dv)/(dx) = vlogv+v` `therefore (dv)/(vlogv) = (dx)/x` `therefore log(logv)=logx+logc=logcx` `therefore logy/x=cx` |
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