1.

`x(dy)/(dx)=y(logy-logx+1)`A. `logx/y=cy`B. `logy/x=cy`C. `logy/x=cx`D. None of these

Answer» Correct Answer - C
`(dy)/(dx)= y/x[logy/x+1]`
Put `y=vx`
`v+x(dv)/(dx) = vlogv+v`
`therefore (dv)/(vlogv) = (dx)/x`
`therefore log(logv)=logx+logc=logcx`
`therefore logy/x=cx`


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