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x C -b8. If a, b, c are three real numbers, then number of real roots of cx a 0 isb -a X(1) Zero(2) One(4) Three(3) Two |
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Answer» upon calculating the determinant, we get ∆ =x(x²+a²)-c(-cx-ab)-b(ac-bx) = 0∆ = x³+ x(a²+b²+c²) + 2abc = 0 since it is a cubic polynomial , so 3 roots are possible . the question is how many real roots? |
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