X and y can construct a small quarantine center in 12 days , which x a

1.	X and y can construct a small quarantine center in 12 days , which x alone can construct in30 days. in how long y alone can construct it
Answer» ong>GIVEN :- (x + y) can construct a SMALL quarantine center = in 12 days . x ALONE can construct in 30 days. To Find :- in how long y alone can construct it ? Solution :- LCM of 12 and 30 = 60 units = Let Total work . Than, → Efficiency of (x + y) = (Total work) / (Total No. of Days by both) = 60/12 = 5 units / Day. → Efficiency of x alone = (Total work) / (Total No. of Days by x alone) = 60/30 = 2 units / Day. As, we can see efficiency of (x + y) is 5units / day and efficiency of x alone is 2 units/day . Therefore, → Efficiency of y alone = (x + y) - x → Efficiency of y alone = 5 - 2 = 3 units / Day. Hence, → Time taken by y alone to complete Total work alone = (Total work) / (Efficiency of y alone) = 60/3 = 20 Days. (Ans.) ∴ y alone can construct the small quarantine center alone in 20 days.

X and y can construct a small quarantine center in 12 days , which x alone can construct in30 days. in how long y alone can construct it

Answer»

ong>GIVEN :-

To Find :-

Solution :-

LCM of 12 and 30 = 60 units = Let Total work .

Than,

→ Efficiency of (x + y) = (Total work) / (Total No. of Days by both) = 60/12 = 5 units / Day.

→ Efficiency of x alone = (Total work) / (Total No. of Days by x alone) = 60/30 = 2 units / Day.

As, we can see efficiency of (x + y) is 5units / day and efficiency of x alone is 2 units/day .

Therefore,

→ Efficiency of y alone = (x + y) - x

→ Efficiency of y alone = 5 - 2 = 3 units / Day.

Hence,

→ Time taken by y alone to complete Total work alone = (Total work) / (Efficiency of y alone) = 60/3 = 20 Days. (Ans.)