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X=a sin theta+b cos theta ,y=a cos theta -b sin theta,prove that x2+y2=a2+b2 |
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Answer» Step-by-step EXPLANATION: LET '* ● *' as theta x = asin● + bcos● y = acos● - bsin● now x² + y² (asin● + bcos●)² + (acos● - bsin●)² a²sin²● + b²cos²● + 2a bsin●cos● + a²cos● + b²sin²● - 2AB sin●cos● a²sin²● + a²cos²● + b²cos²● + b²sin²● a² (sin²● + cos²●) + b² (sin²● + cos²●) *{ since sin²● + cos²● = 1}* a² + b² proved |
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