x = 5, y = 2 is a solution of the linear equation (A) x + 2 y = 7 (B

1.	x = 5, y = 2 is a solution of the linear equation (A) x + 2 y = 7 (B) 5x + 2y = 7 (C) x + y = 7 (D) 5 x + y = 7
Answer» (C) x + y = 7 (a) Take x + 2y, on putting x = 5 and y = 2, we get 5 + 2(2) = 5 + 4 = 9 ≠ 7. So, (5, 2) is not a solution of x + 2y = 7 (b) Take 5x + 2y, on putting x = 5 and y = 2, we get 5 x 5 + 2 x 2 = 25 + 4 = 29 ≠ 7 So, (5, 2) is not a solution of 5x + 2y = 7. (c) Take x + y, on putting x = 5 and y = 2, we get 5 + 2 = 7 So, (5,2) is a solution of x + y = 7. (d) Take 5x + y, on putting x = 5 and y = 2, we get 5 × 5 + 2 = 25 + 2 = 27 ≠ 7 So, (5, 2) is not a solution of 5x + y = 7.

x = 5, y = 2 is a solution of the linear equation (A) x + 2 y = 7 (B) 5x + 2y = 7 (C) x + y = 7 (D) 5 x + y = 7

Answer»

(C) x + y = 7

(a) Take x + 2y, on putting x = 5 and y = 2, we get
5 + 2(2) = 5 + 4 = 9 ≠ 7.

So, (5, 2) is not a solution of x + 2y = 7

(b) Take 5x + 2y, on putting x = 5 and y = 2, we get
5 x 5 + 2 x 2 = 25 + 4 = 29 ≠ 7

So, (5, 2) is not a solution of 5x + 2y = 7.

(c) Take x + y, on putting x = 5 and y = 2, we get 5 + 2 = 7

So, (5,2) is a solution of x + y = 7.

(d) Take 5x + y, on putting x = 5 and y = 2, we get
5 × 5 + 2 = 25 + 2 = 27 ≠ 7

So, (5, 2) is not a solution of 5x + y = 7.