(x-5) person can do a work in x days and (x+5) person can do 75 % of t

1.	(x-5) person can do a work in x days and (x+5) person can do 75 % of the same work in (x-11) days. Then in how many days can (x+10) person finish the work? * a. 15 days b.10 days c.20 days d. 24 days
Answer» ANSWER: Answer: 12 days Explanation: 34×(x−2)x=(x+7)(x−10)34×(x-2)x=(x+7)(x-10) ⇒x2−6x−280 =0⇒x2-6x-280 =0 => x= 20 and x=-14 so, the ACCEPTABLE values is x=20 Therefore, Total work =(x-2)x = 18 x 20 =360 UNIT Now 360 = 30 x k => k=12 days

(x-5) person can do a work in x days and (x+5) person can do 75 % of the same work in (x-11) days. Then in how many days can (x+10) person finish the work? * a. 15 days b.10 days c.20 days d. 24 days

Answer»

Answer: 12 days

Explanation:

34×(x−2)x=(x+7)(x−10)34×(x-2)x=(x+7)(x-10)

⇒x2−6x−280 =0⇒x2-6x-280 =0

=> x= 20 and x=-14

so, the ACCEPTABLE values is x=20

Therefore, Total work =(x-2)x = 18 x 20 =360 UNIT

Now 360 = 30 x k

=> k=12 days