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X-3y=16,2x-y=4 by elimination method |
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Answer» Answer: Use elimination to solve: L1 x+3y=16 L2 2x-y=4 Multiply L2 by 3 so that when you ADD L1+L2 the y's cancel so that you can solve for x. L2 3(2x-y)=3(4) ---> 6x-3y=12 Now add this to L1: x+3y=16 6x-3y=12 _________ 7x+0=28 7x=28 7x/7=28/7 x=4 Now substitute 4 in for x in either L1 or L2 and solve for y, I'm going with L1: (4)+3y=16 4+3y=16 4-4+3y=16-4 3y=12 3y/3=12/3 y=4 The solution (x,y) is (4,4) HAPPY CALCULATING!!! |
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