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(X 3SOROLN(90 — ) — sec(90 — ) cos ecl+ sin® 25+ sin® 65 + /3 tan 61an 16tan 74 tan 84 |
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Answer» Cotθ.tan(90°-θ)-sec(90°-θ)cosecθ+(sin²35°+sin²55°)+√3(tan5°.tan15°.tan30°.tan75°.tan85°)=cotθ.cotθ-cosecθ.cosecθ+sin²35°+sin²(90°-35°)+√3{tan5°.tan15°.(1/√3).tan(90°-15°).tan(90°-5°)}=cot²θ-cosec²θ+sin²35°+cos²35°+√3×1/√3(tan5°tan15°cot15°cot5°)=-1+1+{tan5°tan15°(1/tan15°)(1/tan5°)}=1 |
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