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X^3+y^3, if x+y=3, and xy=2 |
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Answer» Answer: Step-by-step EXPLANATION: first (x+y)^2= x^2 + y^2 + 2xy 3^2= x^2 +y^2 + 2(2) 9 = x^2 + y^2 + 4 9-4= x^2 + y^2 5 = x^2 +y^2 now x^3+y^3 = (x+y)(x^2 + y^2 - xy) x^3+y^3 = (3)((5) - (2)) x^3+y^3= 3*3 x^3+y^3 = 9 |
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