1.

X+2y=5,3x-4y=26 by elimination method

Answer»

ANSWER:

(x+2y=5) ×3

=3X+6y=15...... eq 1

3x-4y=26...eq 2

now, eq 1-eq 2=>10y= -11

=>y=-11/10

again,

eq1=>3x+(6×-11/10) =15

=>3x+(-66/10) =15

=>3x=15 +66/10

=>3x=150+66/10

=>3x=216/10

=>x=216/10×3


Discussion

No Comment Found

Related InterviewSolutions