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X + 2Solve:II2x - 33x - 7x + 3​

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ANSWER:

\frac{x + 2}{x + 3}  =  \frac{2x - 3}{3x - 7} \\ (x + 2)(3x - 7) = (2x - 3)(x + 3) \\ x(3x - 7) + 2(3x - 7) = x(2x - 3) + 3(2x - 3) \\ 3 {x}^{2}  - 7x + 6x - 14 = 2 {x}^{2}  - 3x + 6x - 9 \\ 3 {x}^{2}  - 2 {x}^{2} - 7x + 3x + 6x - 6x = 14 - 9 \\  {x}^{2}   - 4x = 5 \\  {x}^{2}  - 4x - 5 = 0 \\  {x}^{2}  - (5 - 1)x - 5 = 0 \\  {x}^{2}  - 5x + x - 5 = 0 \\ x(x - 5)  + 1(x - 5) = 0 \\ (x - 5)(x + 1) = 0 \\ x = 5 \:  \: or  \: \: x =  - 1

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