1.

X^2 + Kx - 68= 0.find the value of x​

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ANSWER:

ANSWERGiven,kx(x−2)+6=0kx2−2kx+6=0Since the roots are equal,⇒b2=4ac(−2k)2=4(k)(6)4k2=4k(6)∴k=6



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