1.

x^2 %2B x*(a/(a %2B b) %2B (a %2B b)/a) %2B 1=0

Answer»

Let --> y = ( a / ( a + b )) ;

--> x² + [ y + 1/y ]x + 1 = 0

=> yx² + [ y² + 1 ] x + y = 0

=> yx² + y²x + x + y = 0

=> [ yx + 1 ][ x + y ] = 0

=> x = [ - 1 / y ] || x = - y

=> x = [ ( - a - b ) / a ], x = [ -a / ( a + b ) ]



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