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(x^2 %2B 2*x)*(x^2 %2B 2*x - 11) %2B 24=0 |
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Answer» let x^2+2x= pp(p-11)+24=0p^2-11p+24=0p^2-8p-3p+24=0p (p-8)-3(p-8)=0(p-8)(p-3)=0putting the value of p (x^2+2x-8)(x^2+2x-3)=0{x^2+4x-2x-8}{x^2+3x-x-3}=0{x(x+4)-2(x+4)}{x(x+3)-1(x+3)}(x+4)(x-2)(x+3)(x-1) x^2+2x=0, p^2-8p-3p+24; p(p-8)-3(p-a)=0( p-3)(p-3)=0; ( x^2+4x-2x-8)( x^2+3x-3)= (x(x+4)-2(x+4)-(x)(x+3)(x-1) (x+4)(x-2)(x+3)(x-1) |
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