1.

X+1/x=root 2 find value of x²+1/x²

Answer»

Given \: x + \frac{1}{x} = \sqrt{2} \: --(1)

/* On SQUARING both SIDES of EQUATION (1), we GET*/

\implies \Big( x + \frac{1}{x}\Big)^{2} = (\sqrt{2})^{2}

\implies x^{2} + \frac{1}{x^{2}} + 2 \times x \times \frac{1}{x} = 2

\implies x^{2} + \frac{1}{x^{2}} + 2 = 2

\implies x^{2} + \frac{1}{x^{2}} = 2 - 2

\implies x^{2} + \frac{1}{x^{2}} = 0

THEREFORE.,

\red { The \: value \:of \: x^{2} + \frac{1}{x^{2}} }\green{= 0}

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