1.

(x+1)(x+2)(x+3)(x+4)=8 factories this equation

Answer»

Answer:

{-5±i√7}/2 , {-5±√17}/2

Step-by-step EXPLANATION:

(x+1)(x+4)(x+2)(x+3)=8

( x²+5x+4)(x²+5x+6)=8

let x²+5x=k

(k+4)(k+6)=8

k²+10k+24=8

k²+10k+24-8=0

k²+10k+16=0

K²+8k+2k+16=0

k(k+8)+2(k+8)=0

(k+2)(k+8)=0

k=-2, -8

x²+5x=-8

x²+5x+8=0

now compare with the general EQUATION of quadratic

x²+5x+8=0

ax²+bx+C=0

a=1 b=5 c =8

using the almighty formula

{-b±√(b²-4ac)}/2a

-5±√(25-32)/2

{-5±i√7}/2

now k=-2

x²+5x=-2

x²+5x+2=0

{-5±√(25-8)}/2

{-5±√17}/2

Hope it will help you

Thanku



Discussion

No Comment Found

Related InterviewSolutions