1.

(x+1) (x+2) (3x-1) (3x-4)+12

Answer»
=  ({x  }^{2}  + 3x + 2)(9 {x}^{2}  - 15x + 4) + 12 \\ =  ( {x}^{2}  + 3x  + 2) (1)(9 - 5 + 2) + 12 \\   =  ({x}^{2}  + 3x + 2)(6) + 12 \\  = 6 {x}^{2}  + 18x + 24


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