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X+1 = p ÷ x³+2x²-5kx-7 |
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Answer» Answer: ⇢ K = 2x^5 - x4 - 8x^3 + p/5x^4 Step-by-step explanation: ⇢ x + 1 = p x^3 + 2x^2 - 5KX - 7 ⇢ x^4 + x^3 = -5k x^4 + 2x^5 - 7x^3 + p ⇢ -5kx^4 + 2x^5 - 7x^3 + p = x^4 + x^3 ⇢ -5kx^4 + 2x^5 - 7x^3 + p + -2x^5 = x^4 + x^3 + -2x^5 ⇢ -5kx^4 - 7x^3 + p = - 2x^5 + x^4 + x^3 ⇢ -5kx^4 - 7x^3 + p + 7x^3 = -2x^5 + x^4 + x^3 + 7x^3 ⇢ -5kx^4 + p = -2x^5 + x^4 + 8x^3 ⇢ -5kx^4 + p + -p = -2x^5 + x^4 + 8x^3 + - p ⇢- 5kx^4 = -2x^5 + x^4 + 8x^3 - p ⇢ -5kx4/-5x4 = -2x^5 + x^4 + 8x^3 - p/-5x^4 ⇢ k = 2x^5 - x4 - 8x^3 + p/5x^4 |
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