1.

x=1+a+a2+...∞(a<1)y=1+b+b2+...∞(b<1)Then the value of 1+ab+a2b2+.....∞ is[MNR 1980; MP PET 1985]

Answer»

x=1+a+a2+...(a<1)

y=1+b+b2+...(b<1)

Then the value of 1+ab+a2b2+..... is

[MNR 1980; MP PET 1985]





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