1.

(x+1)^2-x^2=0 has how many real roots Fast guys

Answer»

ANSWER:

\huge\purple {\mathfrak{Bonjour  Mate!}}

(x^2+1)^2-x^2=0

(x^2+1)^2=x^2

rooting on both sides

we GET

x^2+1=x x^2+1=-x

x^2-x+1=0 x^2+x+1=0

det of EQUATIONS is LESS than zero

hence they have IMAGINARY roots



Discussion

No Comment Found

Related InterviewSolutions