Saved Bookmarks
| 1. |
(x+1)^2-x^2=0 has how many real roots Fast guys |
|
Answer» (x^2+1)^2-x^2=0 (x^2+1)^2=x^2 rooting on both sides we GET x^2+1=x x^2+1=-x x^2-x+1=0 x^2+x+1=0 det of EQUATIONS is LESS than zero hence they have IMAGINARY roots |
|