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Write the zeros of the polynomial x²-5x-6

Answer» Let p(x) = x2 \x96 5x + 6= x2 \x96 3x \x96 2x + 6= x(x \x96 3) \x96 2(x \x96 3)= (x \x96 3)(x \x96 2)∴ (x \x96 3)(x \x96 2) = 0⇒ x \x96 3 = 0 or x \x96 2 = 0⇒ x = 3 or x = 2Thus 3 and 2 are the zeroes of the given polynomial Sum of roots (α+ β) = (3+2) = 5 = − (−5/1) = − (b/a) Product of roots (αβ) = 3 × 2 = 6 = (6/1) = (c/a)


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