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Write the vector equation of the following line:`(x-5)/3=(y+4)/7=(6-z)/2` |
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Answer» Let `(x-5)/3 = (y+4)/7 = (6-z)/2 = lambda` Then, `=>x = 3lambda+5` `=>y = 7lambda-4` `=>z = -2lambda+6` `:. vecr = xhati+yhatj+zhatk` `=>vecr = (3lambda+5)hati+(7lambda-4)hatj+(-2lambda+6)hatk` `=>vecr = (5hati-4hatj+6hatk)+lambda(3hati+7hatj-2hatk)`,which is the required vector equation. |
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