Write the third equation of motion and it's solutions

1.	Write the third equation of motion and it's solutions
Answer» Explanation: The TOTAL distance travelled, S = Area of trapezium OABC. So, S= 1/2(SumofParallelSides)×Height S=(OA+CB)×OC Since, OA = u, CB = v, and OC = t The above equation becomes S= 1/2(u+v)×t Now, since t = (v – u)/ a The above equation can be WRITTEN as: S= 1/2(u+v)×(v-u)/a Rearranging the equation, we get S= 1/2(v+u)×(v-u)/a S = (v2-u2)/2a Third equation of motion is obtained by solving the above equation: v2 = u2+2aS Derivation of Third Equation of Motion by Calculus METHOD It is known that, Derivation Of Equation Of Motion These were the detailed derivations for EQUATIONS of motion in the graphical method, algebraic method and calculus method.

Answer»

Explanation:

The TOTAL distance travelled, S = Area of trapezium OABC.

So, S= 1/2(SumofParallelSides)×Height

S=(OA+CB)×OC

Since, OA = u, CB = v, and OC = t

The above equation becomes

S= 1/2(u+v)×t

Now, since t = (v – u)/ a

The above equation can be WRITTEN as:

S= 1/2(u+v)×(v-u)/a

Rearranging the equation, we get

S= 1/2(v+u)×(v-u)/a

S = (v2-u2)/2a

Third equation of motion is obtained by solving the above equation:

v2 = u2+2aS

Derivation of Third Equation of Motion by Calculus METHOD

It is known that,

Derivation Of Equation Of Motion

These were the detailed derivations for EQUATIONS of motion in the graphical method, algebraic method and calculus method.

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