Write the polynomial the product and sum of whose zeros are negative 9

1.	Write the polynomial the product and sum of whose zeros are negative 9 by 2 and 3 by 2
Answer» ANSWER: let the the ZEROS be $\alpha \: \: and \: \: \: \: \: \beta$ and ... Step-by-step explanation: as product of zeros= as SUM of zeros = $\alpha + \beta = \frac{ - b}{a}$ so $\frac{ - 9}{<klux>2</klux>} = \frac{ - b}{a}$ so a= 2 and b= 9. now product of zeros $\alpha \beta = \frac{c}{a}$ $\frac{3}{2} = \frac{c}{a}$ that is. c= 3... SO *OUR* *POLINOMIAL WOULD BE.... ${2x}^{2} + 9x + 3$ hope* it helps ; )