1.

Write the Nernst equation and calcualte emf of the following cell at 298 K: Mg(s) | Mg^(2+) (0.1 M ) || Cu^(2+) (0.01 M) | Cu(s) Given: E_("cell")^(@) = 2.71 V

Answer»

Solution :Nernst equation for the CELL may be written as:
`E_("cell") =E_("cell")^(@) -(0.0591)/N log ([MG^(2+)])/([Cu^(2+)])M`
Substituting the VALUES in the above equation, we have
`I_("cell")^(-) =2.71 V - (0.0591)/2 log ([0.1])/([0.01]) = 2.71 V - 0.00295 xx 1 = 2.68 V`


Discussion

No Comment Found

Related InterviewSolutions