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Write the molecular orbital electron distribution of oxygen `(O_(2))` Specify its bond order and magnetic property Fill in the blanks When `N_(2) ` goes to `N_(2)^(o+)`, the `N-N` bond distance___ and when `O_(2)` goes to `O_(2)^(o+)` the `O-O` bond distance ____ .A. increase, decreaseB. decrease, increaseC. increased in both the casesD. decreased in both the cases |
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Answer» Correct Answer - a When `N_(2)^(+)` is formed from `N_(2)`, the electron is lost from the bonding molecular orbital and thus the bond order decreases. Consequently, the bond distance increases . When `O_(2)^(+)` is formed the electron is lost from an antibonding molecular orbital. Obviously , the bond order increases and the distance decreases. |
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