1.

Write the middle term in the expension of (x2\xa0- yx)12\xa0.\xa0

Answer» total number of terms in expansion = (power of expression +1)so in this expension total number of terms ll be 13 and middle term ll be 7th termT7\xa0=\xa012C6\xa0({x)2}6\xa0(yx)6\xa0


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