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Write the integrating factor of (x log x) \(\frac{dy}{dx}\) + y = 2 log x |
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Answer» From the given differential equation, we have \(\frac{dy}{dx}+\frac{1}{x\,log\,x}.y=\frac 2x\) So, If = \(e^{\int\frac{1}{x\,log\, x}dx}\)\(=e^{log|(log\,x)|}= log\,x\) |
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