1.

Write the following sets in roster from: J = {x : ϵ R and x2 + x – 12 = 0}

Answer»

The given equation is:

x2 + x – 12 = 0 

⇒ x2 + 4x – 3x – 12 = 0 

⇒ x(x + 4) – 3(x + 4) = 0 

⇒ (x – 3)(x + 4) = 0 

⇒ x – 3 = 0 or x + 4 = 0 

⇒ x = 3 or x = -4 

therefore, the solution set of the given equation can be written in roaster form as {3, -4}

So, J = {3, -4}



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