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Write the following sets in roster from: J = {x : ϵ R and x2 + x – 12 = 0} |
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Answer» The given equation is: x2 + x – 12 = 0 ⇒ x2 + 4x – 3x – 12 = 0 ⇒ x(x + 4) – 3(x + 4) = 0 ⇒ (x – 3)(x + 4) = 0 ⇒ x – 3 = 0 or x + 4 = 0 ⇒ x = 3 or x = -4 therefore, the solution set of the given equation can be written in roaster form as {3, -4} So, J = {3, -4} |
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