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Write the following in roster formThe sets of all positive roots of the equation (x-1)(x+1)(x^2-1)=0 |
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Answer» {1,1} Step-by-step EXPLANATION: (x-1)(x+1)(x^2-1)=0 =>(x-1)(x+1)(x+1)(x-1)=0 since, (x^2-1)=(x+1)(x-1) (x-1)=0 ,x=1 (x+1)=0 ,x=-1 (x-1)=0 ,x=1 (x+1)=0, x=1 since the set contains only positive roots .therefore the set MUST be {1,1). |
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