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Write the electronic configuration of (Z for Ni = 28). |
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Answer» 1 s 2 2 s 22 p 6 3 s 2 3 p 6 4 s 2 3 d 6 in the ground state More correctly the electrons lost are the 4 s 2 leaving 1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 3 d 8 Explanation: NICKEL N i 28 has 28 electrons. 18 electrons fill up the THIRD electron shell leaving 10 valance electrons. 2 electrons in the 4s and 8 elections in the 3d. When Nickel becomes N i + 2 Nickel has lost 2 electrons leaving the atom with only 8 valance electrons. The 4s electrons a lower energy level that the 3d electrons because of the simpler electron path of the S orbital. So in the ground state the electrons being lost should be the 3d electrons. However the 4s electrons are further from the nucleus so losing the the 2 4s electrons leaves only the third shell electrons making the atoms more stable than losing the 3d electrons. So the SOMEWHAT stable electron configuration of N i + 2 is 1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 3 d 8 |
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