Write the dimensions of a and b in the relation E = \(\frac{b-x^2}{a

1.	Write the dimensions of a and b in the relation E = \(\frac{b-x^2}{a}\) Where E is energy, x is distance and t is time.
Answer» The given relation is E = \(\frac{b-x^2}{a}\) As x is subtracted from b, ∴ dimensions of b are x²; i.e., b = [L²] ∴ We can write equation as E = \(\frac{L^2}{a}\) Or a = \(\frac{L^2}{E}\) = \(\frac{L^2}{[L^2MT^{-2}]}\) = [L⁰M^-1T²]

Write the dimensions of a and b in the relation E = \(\frac{b-x^2}{a}\) Where E is energy, x is distance and t is time.

Answer»

The given relation is E = \(\frac{b-x^2}{a}\)

As x is subtracted from b,

∴ dimensions of b are x²;

i.e., b = [L²]

∴ We can write equation as E = \(\frac{L^2}{a}\)

Or a = \(\frac{L^2}{E}\) = \(\frac{L^2}{[L^2MT^{-2}]}\) = [L⁰M^-1T²]