1.

Write the derivative of sinx with respect to cos x

Answer»

d(sinx)d(COSX)=d(sinx)dx⋅DXD(cosx)

We know the derivatives of sin and cos:

d(sinx)dx=cosx

and

d(cosx)dx=−sinx

Also by the chain RULE, we have:

dxd(cosx)=−1sinx

So we have:

d(sinx)d(cosx)=−cosxsinx=−cotx  


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