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Write the decimal expansion of 27/2²5³ without actual dividing it |
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Answer» Step-by-step EXPLANATION: GIVEN: A galvanometer of 100 resistance gives full scale deflection with 0.01A current To find the resistance that should be connected convert it into an ammeter of range 10A Solution: Galvanometer is a very sensitive INSTRUMENT therefore it cannot measure heavy currents. In order to convert a Galvanometer into an Ammeter, a very low shunt resistance is connected in parallel to Galvanometer. Value of shunt is so adjusted that most of the current passes through the shunt. If resistance of galvanometer is R g
and it gives full-scale deflection when current I g
is passed through it. Then, V=I g
R g
⟹V=0.01A×100Ω ⟹V=1V Let a shunt of resistance (R s
) is connected in parallel to galvanometer. If total current through the circuit is I. I=10A=I s
+I g
V=I s
R s
=(I−I g
)R s
(I−I g
)R s
=I g
R g
(10−0.01)R s
=100×0.01 ⟹R s
=0.1Ω is the resistance that should be connected in parallel to convert it into an ammeter of range 10A |
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