Write the cubes of 5 natural numbers which are multiples of 3 and veri

1.	Write the cubes of 5 natural numbers which are multiples of 3 and verify the followings: “The cube of a natural number which is a multiple of 3 is a multiple of 27’
Answer» First 5 natural numbers which are multiple of 3 are = 3 , 6 , 9 , 12 , 15 Now, cube of them are, = 3³ = 3 × 3 × 3 = 27 = 6³ = 6 × 6 × 6 = 216 = 9³= 9 × 9 × 9 = 729 = 12³ = 12 × 12 × 12 = 1728 = 15³ = 15 × 15 × 15 = 3375 We find that all the cubes are divisible by 27, Therefore, “The cube of a natural number which is a multiple of 3 is a multiple of 27’

Write the cubes of 5 natural numbers which are multiples of 3 and verify the followings: “The cube of a natural number which is a multiple of 3 is a multiple of 27’

Answer»

First 5 natural numbers which are multiple of 3 are = 3 , 6 , 9 , 12 , 15

Now, cube of them are,

= 3³ = 3 × 3 × 3 = 27

= 6³ = 6 × 6 × 6 = 216

= 9³= 9 × 9 × 9 = 729

= 12³ = 12 × 12 × 12 = 1728

= 15³ = 15 × 15 × 15 = 3375

We find that all the cubes are divisible by 27,

Therefore, “The cube of a natural number which is a multiple of 3 is a multiple of 27’