1.

Write the cubes of 5 natural numbers which are multiples of 3 and verify the followings:“The cube of a natural number which is a multiple of 3 is a multiple of 27’'

Answer»

As we know that the first 5 natural numbers which are multiple of 3 are 3, 6, 9, 12 and 15

So now,

The cube of 3, 6, 9, 12 and 15

33 = 3 × 3 × 3 

= 27

63 = 6 × 6 × 6 

= 216

93 = 9 × 9 × 9 

= 729

123 = 12 × 12 × 12

= 1728

153 = 15 × 15 × 15 

= 3375

All the cubes are divisible by 27

∴ “The cube of a natural number which is a multiple of 3 is a multiple of 27’



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