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Write the cubes of 5 natural numbers which are multiples of 3 and verify the followings:“The cube of a natural number which is a multiple of 3 is a multiple of 27’' |
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Answer» As we know that the first 5 natural numbers which are multiple of 3 are 3, 6, 9, 12 and 15 So now, The cube of 3, 6, 9, 12 and 15 33 = 3 × 3 × 3 = 27 63 = 6 × 6 × 6 = 216 93 = 9 × 9 × 9 = 729 123 = 12 × 12 × 12 = 1728 153 = 15 × 15 × 15 = 3375 All the cubes are divisible by 27 ∴ “The cube of a natural number which is a multiple of 3 is a multiple of 27’ |
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