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Write the correctly balanced net ionic equation for the reaction whose equilibrium constant at 298 K is:(i) ka (CaH5COOH) = 6.3 x 10-5(ii) ka (H2C2O4) = 5.4 x 10-2(iii) ka (HSO3-) = 2.8 x 10-7(iv) kb (CC1-) = 9.1 x 10-7(v) kb (CH3NH2) = 4.2 x 10-4(vi) ka (H2S) = 1.0 x 10-7(vii) ka (HCN) = 4.0 x 10-10(viii) kb (NH3) = 1.8 x 10-5(ix) ka (H2S) = 1.0 x 10-7 |
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Answer» (i) CaH5COOH ⇌ C6H5COO− + H+ (ii) H2C2O4 ⇌ C2O42− + 2H+ (iii) HSO3 ⇌ H+ + SO32- (iv) C1-H2O ⇌ OH- + HC1 (v) CH3NH2 + H2O ⇌ CH3NH3+ + OH- (vi) H2S ⇌ H+ + HS- (vii) HCN ⇌ H+ + CN- (viii) NH3 + H2O ⇌ NH4+ + OH- (ix) H2S + 2H2O ⇌ S2- + H3O+ |
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