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Write oxidation state of chromium and cobalt in this two compounds |
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Answer» I) Let, X be the OXIDATION number of Cr in [Cr(NH3)6]
Now, x+6×(0)+3×(−1)=0 x−3=0 ⇒x=+3. Oxidation number of Cr is =+3 ii) Let x be the oxidation state of Co in [Co(CN)6]. Since the OVERALL charge on the complex is −3, the sum of oxidation states of all elements in it should be EQUAL to −3. Therefore, x+6(−1)=−3 or, x=+3. xxxxxxxxxxxxxxxxxxxxxx |
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