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| 1. |
Write in polar form1+7i/(2-i) ² |
| Answer» Let r cos θ = –1 and r sin θ = 1On squaring and adding, we obtain r2\xa0(cos2\xa0θ + sin2\xa0θ) = 1+ 1⇒ r2\xa0(cos2\xa0θ + sin2\xa0θ) = 2⇒ r2\xa0= 2 [cos2\xa0θ + sin2\xa0θ = 1]This is the required polar form. | |