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Write equation of solubility product for 1) BaSO4 2)CaF2. 3)Bi2S3 |
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Answer» 1) The solubility PRODUCT (Ksp) of BaSO4 is 1.5 × 10-9 . CALCULATE the solubility of barium sulphate in pure WATER and in 0.1M BaCl2 .2). The solubility of calcium fluoride in saturated solution, it its solubility product is `3.2 xx 10.3). K sp (Bi 2 S 3 )=[Bi 3+ ] 2 [S 2− ] 3 =(2s) 2 ×(3s) 3 =1.2×10 −98 K sp =108s 5 =1.2×10 −98 s 5 = 1081.2 ×10 −98 s 5 ≃1×10 −100 Hence, s≃1×10 −20 . |
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