1.

Write electron configuration for the following ions: (5) (i) Fe3+ (ii) Cr3+ (iii) Pb2+ (iv) Pb 4+ (v) O2

Answer»

Fe3+=1s2 2s2 2p6 3S2 3p6 4S2 3d3
Cr3+=1s2 2s2 2p6 3s2 3p6 4s2 3d1
Pb2+= [XE] 6s2 4f14 5d10
Pb4+= [Xe] 4f14 5d10
O2= 1s2 2s2 2p6 3s2 3P4



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