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Write down the equation of a freely falling body under gravity. |
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Answer» Solution :(i) Distanced traveled by an object falling for time .t., u = 0 , s = d , a = g `s = ut + 1/2 at^2` ` therefore = 1/2 "GT"^2` Time .t. TAKEN for an object to FAIL distance .d.. ` t = sqrt((2d)/(g))` Instantaneous VELOCITY `v_i`of a falling object after elapsed time .t. ` v_i = sqrt(2gd)` Instantaneous velocity `v_i`of a falling object that has traveled distance .d. ` v_i = sqrt(2gd)` (ii) ` u = - 19.6 ms^(-1)` `u = 9.8 ms^(-2)` t = 6 sec height of the building ` s = ut + 1/2 at^2` ` = (-19.6 XX 6) + 1/2 (9.8)(6)^2 = - 117.6 + 176.4` s = 58.8 m |
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