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write ĂĽll tIUI 2HanaA v2-1, then proveA cos A =2v2 |
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Answer» TanA=√2-1or, tanA=(√2-1)(√2+1)/(√2+1)or, tanA=(2-1)/(√2-1)or, tanA=1/√2-1∴, tanA+1/tanA=1/√2-1+√2-1or, (tan²A+1)/tanA=[1+(√2-1)²]/(√2-1)or, sec²A/tanA=(1+2-2√2+1)/(√2-1)or, (1/cos²A)/(sinA/cosA)=(4-2√2)/(√2-1)or, 1/sinAcosA=(4-2√2)(√2+1)/(√2-1)(√2+1)or, 1/sinAcosA=(4√2-4+4-2√2)/(2-1)or, 1/sinAcosA=2√2or, sinAcosA=1/2√2 |
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