Write a quadratic polynomial , whose zeroes are -4 and 3

1.	Write a quadratic polynomial , whose zeroes are -4 and 3
Answer» ANSWER: THE ANSWERS IS ${x}^{2} + x - 12$ Step-by-step explanation: THE FORMULA TO FIND QUADRATIC POLYNOMIAL IS $k[ {x}^{2} - ( \alpha + \beta )x + ( \alpha \beta]$ THERE FORE, $here \: \\ \alpha = - 4 \\ and \: \beta = 3 \\ \\ \: k[ {x}^{2} - ( - 4 + 3)x + ( - 4 \times 3)] \\ k( {x}^{2} - ( - 1)x - 12) \\ k( {x}^{2} + 1x - 12) \\ \\ when \: there \: is \: no \: denomintor \: in \: the \: given \: zeroes \: then \: k \: value \: is \: \\ 1 \\ there \: fore \: \\ {x}^{2} + x - 12$ HOPE IT WILL HELP YOU PLZZ MARK AS BRAINLIST

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